I apologize if this kills the imagination of the thread, but I think some math is in order, because 80% isn't really that large.
I mean, forget looking at a world where gays outnumber heterosexuals and TSs outnumber people whose gender matches assigned sex. Let's just put them even for the moment, with a substantial share who don't fit neatly into the "extremes."
Gender matches declared sex: 40%
TS: 40%
Intersex or non-binary gender: 20%
Hetero (among gender binary population): 40%
Gay (among gender binary population): 40%
Bi/pan/etc (among gender binary population): 20%
I'm going to assume that gender/sex congruity has no correlation with sexual orientation. That is, someone is just as likely to be "straight" if they are TS as if their gender matches the declared sex. In this event, the probability of a person being both straight and gender-matching-sex would be:
P(both) = P(first) * P(second) = 0.4 * 0.4 = 0.16 = 16%
This is to say that 16% of the population would be non-LGBTI (most of that T, anyway), which is already placing LGBTQQI at 84%, with the QQ crowd still not fully factored in. As such, 80% is generally not capable of flipping the discrimination roles (it would be mathematically possible for gays/lesbians significantly outnumber heteroseuxals to achieve the 80% number, but the other dimensions would give rise to the traditional minorities).
The basic math trick involved here is that someone ends up as LGBTQQI by merely possessing at least one letter (a "big tent" approach that gives someone multiple ways of getting in), whereas not being a LGBTQQI requires exactly no letters match (which gives someone only one way in). If all ways are equal in proportion, then LGBTQQI gets a really high percent simply by controlling almost all the combinations, whereas not-LGBTQQI only gets one.
(I'll probably reply later regarding the intended purpose of the thread, but I needed to get this particular math observation off my chest.)
